Squareroot (y-1) + 3 = y

Note:xy means x times y and x (y) means the same thing

so

first we get rid of square root then

make the equation equal to zero becaues if

xy=0 then x or/and y=0

squareroot (y-1) + 3=y

isolate the squareroot

subtrac 3 from boht sides

squareroot (y-1) = y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot (y-1)) ^2 = (y-3) ^2

(y-1) = (y-3) (y-3)

y-1=y^2-6y+9

subtrac y from both sides

-1=y^2-7y+9

add 1 to both sides

0=y^2-7y+10

find what two number multiply to make 10 and add to get - 7

the answer is - 2 and - 5

0 = (y-5) (y-2)

therfore

y-5=0

and/or

y-2=0

therefor

y=5 or/and 2 might work

let's try out 2

square root (2-1) + 3=2

square root (1) + 3=2

1+3=2

false

so 2 doesn't work

let's try 5

squareroot (5-1) + 3=5

squareroot (4) + 3=5

2+3=5

5=5

true

y=5