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16 October, 00:11

Squareroot (y-1) + 3 = y

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  1. 16 October, 00:30
    0
    Note:xy means x times y and x (y) means the same thing

    so

    first we get rid of square root then

    make the equation equal to zero becaues if

    xy=0 then x or/and y=0

    squareroot (y-1) + 3=y

    isolate the squareroot

    subtrac 3 from boht sides

    squareroot (y-1) = y-3

    square both sides (since they are equal, you should be able to square both sides and still make it true)

    (squareroot (y-1)) ^2 = (y-3) ^2

    (y-1) = (y-3) (y-3)

    y-1=y^2-6y+9

    subtrac y from both sides

    -1=y^2-7y+9

    add 1 to both sides

    0=y^2-7y+10

    find what two number multiply to make 10 and add to get - 7

    the answer is - 2 and - 5

    0 = (y-5) (y-2)

    therfore

    y-5=0

    and/or

    y-2=0

    therefor

    y=5 or/and 2 might work

    let's try out 2

    square root (2-1) + 3=2

    square root (1) + 3=2

    1+3=2

    false

    so 2 doesn't work

    let's try 5

    squareroot (5-1) + 3=5

    squareroot (4) + 3=5

    2+3=5

    5=5

    true

    y=5
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