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17 August, 05:23

Find an equation of the plane that passes through the origin and its perpendicular to the vector [1,-2,5]

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  1. 17 August, 05:47
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    x - 2y + 5z = 0

    Step-by-step explanation:

    The standard equation is of the form, Ax + By + Cz = 0

    The equation of the plane that passes through the origin (0, 0, 0) and is perpendicular to [1, - 2, 5] is

    A = 1, B = - 2, C = 5

    x = y = z = 0 (at origin)

    A (x-0) + B (y-0) + C (z-0) = 0

    (x - 0) - 2 (y-0) + 5 (z-0) = 0

    x - 2y + 5z = 0
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