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15 June, 23:53

There were 28,000 people at a ball game in Los Angeles. The day's receipts were $154,000.

How many people paid $11 for reserved seats and how many paid $4 for general

admission?

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  1. 15 June, 23:58
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    There were 6,000 reserved seats and 22,000 general admission seats.

    Step-by-step explanation:

    Using the information given, we can create a system of equations.

    X will represent the reserved seats and Y will represent the general admission seats.

    x+y=28000

    11x+4y=154000

    The first equations is how many people are attending and the second question is the amount of money gained. We want to make the equations equal by doing the following:

    x+y=28000

    y=28000-x

    By subtracting x from both sides, we have an equation equal to y, which we can plug in.

    11x+4 (28000-x) = 154000

    11x+112000-4x=154000

    7x=42000

    x=6000

    We now have the amount of reserved seats, which we can plug into the frist equation.

    6000+y=28000

    y=22000
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