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20 July, 13:19

Solve on the interval [0, 2pi) : 3 sec x - 2 = 1

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  1. 20 July, 13:33
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    First we rewrite the expression:

    3sec (x) - 2 = 1

    3 (1 / cos (x)) - 2 = 1

    3 (1 / cos (x)) = 1 + 2

    3 (1 / cos (x)) = 3

    (1 / cos (x)) = 3/3

    cos (x) = 1

    x = 2 * pi * n

    on the interval [0, 2pi):

    x = 0

    Answer:

    x = 0 on the interval [0, 2pi)
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