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Mathematics
24 March, 19:05
what is 6 more than 7 times a number is 41
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Marley Jarvis
24 March, 19:23
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the problem would be set up as 6 + (7*x) = 41
first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41
7x = 41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 = 5.9
so x = 5.9
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