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11 December, 11:02

Consider this system of equations. Which shows the first equation written in slope-intercept form?

2 (2y+10) = 7*

y=8

y = 7x-10

7

y=zx-5

y = 7x-5

o y = 1 x - 5

+5
Answers (1)
  1. 11 December, 11:22
    0
    Question:

    Consider this system of equations. Which shows the first equation written in slope-intercept form?

    ½ (2y + 10) = 7x.

    y = 8.

    A. y = 7x - 10

    B. y = 7x/2 - 5

    C. y = 7x - 5

    D. y = 7x/4 - 5

    Answer:

    C. y = 7x - 5

    Step-by-step explanation:

    Given

    ½ (2y + 10) = 7x.

    Required

    Convert to slope intercept form.

    To do this, we simply make y the subject of formula from the given equation

    We start by writing out the equation

    ½ (2y + 10) = 7x.

    Then, we open the bracket

    ½ * 2y + ½ * 10 = 7x

    2y/2 + 10/2 = 7x

    y + 5 = 7x

    Then, subtract 5 from both sides of the equation

    y + 5 - 5 = 7x - 5

    y = 7x - 5

    The equation can't be simplified any further. So, we've arrived at a solution

    Hence, the slope intercept form of ½ (2y + 10) = 7x is y = 7x - 5
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