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Juarez
Mathematics
8 January, 08:57
Let f (x) = 16x^2-x. Find f (x+1) - f (x)
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Walker Dillon
8 January, 09:19
0
f (x+1) = 16 (x+1) ² - (x+1) = 16 (x²+2x+1) - x - 1
= 16x² + 32x + 16 - x - 1 = 16x²+31x+15
so
f (x+1) - f (x) = 16x²+31x+15 - (16x² - x)
= 16x²+31x+15 - 16x² + x
= 32x + 15
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