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Clare Shields
Mathematics
21 March, 19:35
Find the derivative g (x) = ln (2x^2+1)
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Marilyn Hartman
21 March, 20:01
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4x / (2x^2+1)
Step-by-step explanation:
g (x) = ln (2x^2+1)
Using u substitution
u = 2x^2 + 1
du = 4x dx
g' (x) = d/du (g (u) du)
We know that the derivative of ln (u) = 1/u since this is always positive
= 1 / u * du
Substituting x back into the equation
g' (x) = 1 / (2x^2+1) * 4x
= 4x / (2x^2+1)
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