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21 March, 19:35

Find the derivative g (x) = ln (2x^2+1)

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  1. 21 March, 20:01
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    4x / (2x^2+1)

    Step-by-step explanation:

    g (x) = ln (2x^2+1)

    Using u substitution

    u = 2x^2 + 1

    du = 4x dx

    g' (x) = d/du (g (u) du)

    We know that the derivative of ln (u) = 1/u since this is always positive

    = 1 / u * du

    Substituting x back into the equation

    g' (x) = 1 / (2x^2+1) * 4x

    = 4x / (2x^2+1)
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