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13 April, 03:52

Find three consecutive even integers, such that

5 times of first integer is 18 more than the sum

of second and third integers.

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Answers (1)
  1. 13 April, 04:22
    0
    8,10,12

    Step-by-step explanation:

    x

    x+2

    x+4

    5x-18 = x+2 + x+4

    5x-18=2x+6

    3x=24

    x=8

    8*5=40 40-18 = 22

    10+12 = 22
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