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8 February, 15:04

Seventy-five times an integer, minus 36, equals 21 times the square of the integer. Which equation could be used to solve for the unknown integer?

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  1. 8 February, 15:14
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    75n-36=21n^2 rearrange so we have an equation equal to zero ...

    21n^2-75n+36=0 divide whole equation by 3

    7n^2-25n+12=0 now factor ...

    7n^2-21n-4n+12=0

    7n (n-3) - 4 (n-3) = 0

    (7n-4) (n-3) = 0

    Since this is an integer 4/7 is extraneous.

    The integer value is 3
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