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18 March, 06:58

Locate the foci of ellipse. Show your work.

X^2/36 + y^2/11 = 1

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  1. 18 March, 07:15
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    In this equation, 36>11 and so the ellipse has major axis along x axis

    standard equation of ellipse with major axis is along x axis

    x^2/a^2+y^2/b^2=1,

    the foci are at (ae, 0) and (-ae, 0)

    eccentricity e is given by

    ae=√ (a^2-b^2)

    In this case ae=√ (36-11) = √25 = + / - 5

    Focii are (-5,0) and (5,0)
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