State the value of the discriminant for each equation. Then determine the number of real solutions of the equation.

1) 0.5x^2-2x=-2

2) 2x^2-5x+20=0

Question

12 April, 01:30

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Cailyn Parks · Answer 1

1) b^2 - 4ac = (-2) ^2 - 4 * (0.5) * 2 = 4 - 4 = 0;

2) b^2 - 4ac = (-5) ^2 - 4*2*20 = 25 - 160 = - 135;

State the value of the discriminant for each equation. Then determine the number of real solutions of the equation.1) 0.5x^2-2x=-22) 2x^2-5x+20=0