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18 May, 20:04

What is the sum of the first five terms of a geometric series with a1=15 and r=1/3

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Answers (2)
  1. 18 May, 20:09
    0
    605/27 or 22.41 to the nearest hundredth.

    Step-by-step explanation:

    The formula for the sum of n terms is

    an = a1 * (1 - r^n) / (1 - r) where a1 = the first term and r = the common difference.

    So here a5 = 15 * (1 - (1/3) ^5) / (1 - 1/3)

    = 605/27

    = 22.41 to the nearest hundredth.
  2. 18 May, 20:21
    0
    15, 5, 5/3, 5/9, 5/27

    Step-by-step explanation:

    Recall, that the general form of a geometric series is

    a, ar, ar², ar³, ...

    where a is the first term and r is the ratio

    It is given that the first time is 15, hence a = 15

    also given that ratio is 1/3

    hence the first 5 terms are:

    15, (15) (1/3), (15) (1/3) ^2, (15) (1/3) ^3, (15) (1/3) ^4

    simplifying each term gives

    15, 5, 5/3, 5/9, 5/27
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