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8 October, 12:46

A rectangle with an area of 240 in2 has a length 10 inches shorter than five times its width. Which equation could be used to solve for the length of the rectangle?

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  1. 8 October, 12:57
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    L = 5W - 10

    5W = L + 10

    W = 1/5 (L + 10)

    Area = L x W

    240 = L (1/5 (L + 10)

    L^2 + 10L = 240 (5) = 1200

    L^2 + 10L - 1,200 = 0
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