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Lance Pierce
Mathematics
30 November, 11:30
Eliminate the parameter. x = t - 3, y = t2 + 5
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Steven Frank
30 November, 11:55
0
y = x^2 + 6x+14
Step-by-step explanation:
x = t - 3, y = t^2 + 5
x=t-3
Add 3 to each side
x+3 = t-3+3
x+3 = t
Substitute into the second equation
y = t^2 + 5
y = (x+3) ^2 + 5
Foil the first term
y = (x+3) (x+3) + 5
y = (x^2 + 3x+3x+9) + 5
y = x^2 + 6x+9) + 5
y = x^2 + 6x+14
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