Three consecutive odd integers are such that the square of the third integer is 9 less than the sum of the squares of the first two. One solution is negative - 3 , - 1 , and 1. Find three other consecutive odd integers that also satisfy the given conditions

Question

Victoria Hardy

Mathematics

2 February, 10:23

Three consecutive odd integers are such that the square of the third integer is 9 less than the sum of the squares of the first two. One solution is negative - 3 , - 1 , and 1. Find three other consecutive odd integers that also satisfy the given conditions

+3

Answers (1)

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Cooper Valencia · Answer 1

Hello,

Let's assume a the first odd integer

a+2 the second,

a+4 the third.

(a+4) ²=a² + (a+2) ²-9

==> a²+8a+16=a²+a²+4a+4-9

==> a²-4a-21=0

Δ=16+4*21=10²

==> a = (4-10) / 2=-3 or a = (4+10) / 2=7

sol n°1 = (-3; -1; 1)

sol n°2 = (7; 9; 11)