Which series of transformations will not map figure H onto itself?

(x + 0, y - 2), reflection over y = 1

(x + 2, y - 0), reflection over x = 3

(x + 3, y + 3), reflection over y = - x + 7

(x - 3, y - 3), reflection over y = - x + 2

Question

Parker Collins

Mathematics

18 April, 06:45

Which series of transformations will not map figure H onto itself?

(x + 0, y - 2), reflection over y = 1

(x + 2, y - 0), reflection over x = 3

(x + 3, y + 3), reflection over y = - x + 7

(x - 3, y - 3), reflection over y = - x + 2

+3

Answers (1)

Know the Answer?

Siena Hampton · Answer 1

(x + 0, y - 2), reflection over y = 1

Step-by-step explanation:

H will be shifted down 2 units and then reflected over y = 1, which maps H into itself

Which series of transformations will not map figure H onto itself?(x + 0, y - 2), reflection over y = 1(x + 2, y - 0), reflection over x = 3(x + 3, y + 3), reflection over y = - x + 7(x - 3, y - 3), reflection over y = - x + 2

Which series of transformations will not map figure H onto itself?

(x + 0, y - 2), reflection over y = 1

(x + 2, y - 0), reflection over x = 3

(x + 3, y + 3), reflection over y = - x + 7

(x - 3, y - 3), reflection over y = - x + 2