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19 August, 23:31

What is the general equation of a sine function with an amplitude of 2, a period of Pi and a horizontal shift of Pi units? y = 2 sine (2 (x minus pi)) y = 2 sine (4 (x + pi)) y = sine (0.5 (x minus pi)) y = sine (2 (x + pi))

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  1. 19 August, 23:40
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    The general equation of the sine function is;

    y = 2 sine (2 (x - π))

    Step-by-step explanation:

    Mathematically, the general equation of a sine function (sinusoid) can be written as;

    y = A sin (B (x-C)) + D

    where, A represents the amplitude

    B is the frequency, where period = 2 π/B

    D is vertical shift

    C is the horizontal or phase shift

    From the question, we have the following;

    Amplitude of 2 (A),

    Period = π

    Since Period = 2 π/B

    This means that π = 2 π/B

    Dividing both sides by π; B = 2

    Horizontal shift = π units = C

    Plugging these values, we have

    y = 2 sine (2 (x - π))
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