The axis of symmetry for the hraph of the function f (x) = 3x^2 + bx + 4 is x=3/2. what is the value of b

Question

Ronan Donaldson

Mathematics

11 December, 14:35

The axis of symmetry for the hraph of the function f (x) = 3x^2 + bx + 4 is x=3/2. what is the value of b

+3

Answers (1)

Know the Answer?

Skyler Huffman · Answer 1

In form f (x) = ax^2+bx+c

the axis of symmetry is - b/2a so

3/2=-b/2a

given

f (x) = 3x^2+bx+4

a=3

b=b

-b / (2*3) = 3/2

-b/6=3/2

-b=18/2

-b=9

b=-9