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11 December, 14:35

The axis of symmetry for the hraph of the function f (x) = 3x^2 + bx + 4 is x=3/2. what is the value of b

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  1. 11 December, 15:00
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    In form f (x) = ax^2+bx+c

    the axis of symmetry is - b/2a so

    3/2=-b/2a

    given

    f (x) = 3x^2+bx+4

    a=3

    b=b

    -b / (2*3) = 3/2

    -b/6=3/2

    -b=18/2

    -b=9

    b=-9
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