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18 January, 19:23

The graph of f (x) = 3 (2/3) ^x?

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  1. 18 January, 19:42
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    Step-by-step explanation:

    The graph of f (x) = 3 (2/3) ^x has the shape of a decaying exponential function. When x = 0, f (0) = 3 (2/3) ^0 = 3, so the y-intercept is (0, 3).

    We know that the graph decays because the base (2/3) is 0 < 2/3 < 1.
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