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28 April, 20:10

F (x) = 4x^2 + 3x + 13 {Find } f (1)

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  1. 28 April, 20:32
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    f (x) = 4x^2+3x+13

    Plug in x=1:

    f (1) = 4 (1) ^2+3 (1) + 13

    =4*1+3+13

    =4+16

    =20

    Answer:

    f (1) = 20
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