How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

25 L

11 L

15 L

Question

2 October, 19:31

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Answers (1)

Know the Answer?

Amaya Valentine · Answer 1

15 L

Step-by-step explanation:

If x is the liters of pure water, then:

0x + 0.25 (10) = 0.10 (x + 10)

2.5 = 0.10x + 1

1.5 = 0.10x

15 = x

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?25 L11 L15 L