Which expression is the completely factored form of x6-64y3?

(x^2 - 4y) (x^4 + 4x^2y + 16y^2)

Step-by-step explanation:

x^6-64y^3

- using the identity a^3 - b^3 = (a - b) (a^2 + ab + b^2) with a = x^2 and b = 4y we have:-

(x^2 - 4y) (x^4 + 4x^2y + 16y^2)