9x^2-12x+4=4 how to sove by square root property

Solve for x over the real numbers using the quadratic formula.

9 x^2 - 12 x + 4 = 4

Subtract 4 from both sides:

9 x^2 - 12 x = 0

9 x^2 - 12 x = 3 (3 x^2 - 4 x):

3 (3 x^2 - 4 x) = 0

Divide both sides by 3:

3 x^2 - 4 x = 0

x = (4 ± sqrt ((-4) ^2 - 4*3*0)) / (2*3) = (4 ± sqrt (16 + 0)) / 6 = (4 ± sqrt (16)) / 6 = (4 ± 4) / 6:

x = (4 + 4) / 6 or x = (4 - 4) / 6

(4 + 4) / 6 = 8/6 = 4/3:

x = 4/3 or x = (4 - 4) / 6

(4 - 4) / 6 = 0/6 = 0:

Answer: x = 4/3 or x = 0