A box has a volume given by the trinomial x^3+4x^2-5x. What are possible dimensions of the box? Use factoring.

A. x, x-5 and x+1

B. x, x+5 and x-1

C. x, x+5 and x+1

D. x, x-5 and x-1

Answer: The correct answer is Choice B.

To factor this expression, we should first factor out the variable x.

We will have:

x (x^2 + 4x - 5)

Now, all we have to do is factor x^2 + 4x - 5.

The factors of this are (x + 5) (x - 1).

If you put all of the factors together, you have: x (x + 5) (x - 1) or Choice B.