F (x) = x ^ 2 + 6x - 4 in vertex form

f (x) = (x + 3) ² - 13

Step-by-step explanation:

The equation of a parabola in vertex form is

f (x) = a (x - h) ² + k

Given

f (x) = x² + 6x - 4

Using the method of completing the square

add/subtract (half the coefficient of the x - term) ² to x² + 6x

f (x) = x² + 2 (3) x + 9 - 9 - 4

f (x) = (x + 3) ² - 13 ← in vertex form

Answer:y = (x-6) ^2-4