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Marie Ali
Mathematics
21 December, 12:57
Find the inverse of the function y=2x^2
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Andrew Dean
21 December, 13:04
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X=2y2x=2y2
Solve for yy.
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y=√2x2,-√2x2y=2x2,-2x2
Solve for yy and replace with f-1 (x) f-1 (x).
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f-1 (x) = √2x2,-√2x2
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Shannon Cordova
21 December, 13:09
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to find the inverse exchange the x and y and then solve for y
y = 2x^2
x = 2y^2
divide by 2
x/2 = y^2
take the square root of each side
sqrt (x/2) = y
the inverse of y = 2x^2 is sqrt (x/2)
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