Will mark brainest! At a local fitness center, members pay a $6 membership fee and $5 for each aerobics class. Nonmembers pay $6 for each aerobic class. For what number of aerobics classes will the cost for members and nonmembers be the same? Thus, for _ aerobics classes, the cost will be the same for members and nonmembers?

Question

Chaya Moyer

Mathematics

4 June, 20:22

Will mark brainest! At a local fitness center, members pay a $6 membership fee and $5 for each aerobics class. Nonmembers pay $6 for each aerobic class. For what number of aerobics classes will the cost for members and nonmembers be the same? Thus, for _ aerobics classes, the cost will be the same for members and nonmembers?

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Answers (2)

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Litzy Fisher · Answer 1

Let's start, before anything, to define our key variable:

x =

We need to find when the cost of aerobics classes for both members and non-members both equal each other.

So let's find the equation for each:

Members pay 6 one time, and then 5 per class, so that would be 6 + 5x

Non-members pay 6 per class, so that would be 6x.

To find when they equal each other, we set their equations equal to each other and solve.

6 + 5x = 6x

subtract

6 = x

So when x, number of aerobics classes, is 6, the cost is the same for members and non-members.

Esperanza Downs · Answer 2

Membership fee = $6.

Cost of each aerobics class = $3.

Slope - intercept form for total cost for members:

y = 3x + 6.

For non-members:

Cost of each aerobics class = $4.

Slope - intercept form for total cost for non-members:

y = 4x.

When cost will be same,

4x = 3x+6.

Solving equation for x now.

Subtracting 3x from right side, we get

4x-3x = 3x-3x+6

x = 6.

Therefore, 6 number of aerobics classes will the cost for members and nonmembers be the same.