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13 January, 19:49

A single die is rolled twice. The set of 36 equally likely outcomes is { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), nbsp (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) }. Find the probability of getting two numbers whose sum is < 13.

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  1. 13 January, 20:13
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    Answer: 1

    Step-by-step explanation:

    Given : A single die is rolled twice.

    The set of 36 equally likely outcomes is { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) }

    The maximum sum of the of two numbers appear on two dices is 12.

    So the event that of getting two numbers whose sum is < 13 is certain and the probability of certain event is 1.

    Thus, the probability of getting two numbers whose sum is < 13 = 1
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