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27 December, 03:06

At 9:00 on Saturday morning, two bicyclist pass each other on a bicycle path. The bicyclist heading north is riding 5km/h faster then the bicyclist heading south. At 10:30, (1.5 hours later) they are 49.5 km apart. Find the two bicyclists' rates.

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  1. 27 December, 03:30
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    Step-by-step explanation:

    One rider's rate is x ... the other is x+4

    Once they pass each other, they travel for 1.5 hrs ... and the combined distance they travel = 39 km

    So ... Rate x Time = Distance ... and we have

    x (1.5) + (x+4) (1.5) = 39 simplify

    1.5x + 1.5x + 6 = 39

    3x + 6 = 39 subtract 6 from both sides

    3x = 33 divide by 3 on both sides

    x = 11 km/hr this si the slower rider's rate

    x + 4 = 11 + 4 = 15 km/hr and this is the faster rider's rate
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