Ask Question
2 March, 19:40

12 A box contains 5 blue balls, 3 black balls and 2

red bals of the same size. A ball is selected at

random from the box and then replaced. A second

ball is then selected Find the probability of

obtaining (a) two red balls. (b) two blue balls or

w black basic) one black ball and one red

palany order

+2
Answers (1)
  1. 2 March, 20:02
    0
    R = red, B=blue, Bl=black

    (a) p (R) X p (R) = 2/10 X 2/10 = 4/100 = 1/25

    (b) p (B) X p (B) = 5/10 X 5/10 = 25/100

    + +

    p (Bl) X p (R) = 3/10 X 2/10 = 6/100 = 37/100

    + +

    p (R) X p (Bl) = 2/10 X 3/10 = 6/100
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “12 A box contains 5 blue balls, 3 black balls and 2 red bals of the same size. A ball is selected at random from the box and then replaced. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers