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1 July, 19:12

You have 276 feet of fencing to enclose a rectangular region. What is the maximum area?

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  1. 1 July, 19:20
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    The perimeter is

    P = 2L + 2W or

    80 = 2L + 2W

    dividing by 2 we get

    40 = L + W

    THe area is

    A = LW

    solving for L, we get

    L = 40-W

    substituting that in, we get

    A = (40-W) (W)

    using completing the square, we get

    A = - (W-20) ^2 + 400

    So, when W = 20, the max area is 400.
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