Mrs. Stevenson wants to split her class into 4 teams: Team A, Team B, Team C, and Team D. There are 28 students in her class. To make sure she splits them evenly, she puts the name of each team on 7 pieces of paper and puts them in a hat. Each student draws one piece of paper from the hat to determine which team he or she will be on. Mrs. Stevenson had Sean draw first and Caleb draw second. What is the probability that Sean and Caleb will both be on Team D? Show answer as a percent rounded to nearest hundredth, if necessary.

Question

Anna Mcgrath

Mathematics

21 September, 22:34

Mrs. Stevenson wants to split her class into 4 teams: Team A, Team B, Team C, and Team D. There are 28 students in her class. To make sure she splits them evenly, she puts the name of each team on 7 pieces of paper and puts them in a hat. Each student draws one piece of paper from the hat to determine which team he or she will be on. Mrs. Stevenson had Sean draw first and Caleb draw second. What is the probability that Sean and Caleb will both be on Team D? Show answer as a percent rounded to nearest hundredth, if necessary.

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Sparky · Answer 1

The probability that both of the students are on Team D is about 5.56%

There are 4 teams, so the first person has a 1/4 chance of being on Team D.

However, for the second person, there are only 6 spots left out of 27 to be on Team D.

To find the combined probability, we need to multiply the two fractions.

1/4 times 6/27 = 1/18 or about 5.56%