What two numbers multiply together and equal 16 and add together and equal - 2?

There is a solution, but you might not have learned how to do it yet

in middle school.

If you've learned to use the quadratic formula to solve a quadratic equations,

then you can do this.

The first requirement says: ' x ' times ' y ' = 16

The second requirement says: (x + y) = - 2

Take the second requirement, and subtract ' x ' from each side:

y = - x - 2

Substitute this into the first requirement:

' x ' times (-x - 2) = 16

Eliminate parentheses:

-x² - 2x = 16

Subtract 16 from each side:

-x² - 2x - 16 = 0

Multiply each side by - 1:

x² + 2x + 16 = 0

Solve this with the quadratic formula, and you get two solutions,

which are the two numbers that satisfy both requirements.

The numbers are

-1 + √-15

-1 - √-15

Check:

- - Product: (-1 + √-15) times (-1 - √-15) = 1 + 15 = 16

- - Sum = - 1 + √-15 - 1 - √-15 = - 2

They work.

yay

None, because both numbers must be negative in order to get a positive answer, or both positive. However, - 2 means that there is at least one negative number, or two negative numbers. the only option : - 1 + (-1) = - 2. So there is no real solution.