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28 February, 06:17

The circle given by x^2+y^2-4x-10=0 can be written in standard form like this: (x-h) ^2+y^2=14. What is the value of h in this equation?

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  1. 28 February, 06:30
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    We just need to complete the square for the x terms

    gropu x terms

    x^2-4x

    take 1/2 of linear coefient and square it

    -4/2=-2, (-2) ^2=4

    x^2-4x+4

    factor

    (x-2) ^2

    h=2
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