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14 September, 09:54

un numero supera en 43 a otro. Si el mayor se divide entre el menor, el cociente es 5 y el residuo es 7. Encontrar los numeros.

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  1. 14 September, 10:11
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    The smaller number is 9 and the greater number is 52.

    Explanation:

    1. Name the smaller number x and the greater number y

    2. One number is 43 greater than the other:

    y - x = 43 [equation 1]

    3. If the greater numbrer is divided by the smaller, the quotient is 5 and the remainder is 7:

    y = 5x + 7 [equation 2]

    4. Substitute y into the equation 1, to find x:

    5x + 7 - x = 43 4x = 43 - 7 4x = 36 x = 36 / 4 x = 9

    5. Substitute x = 9 into the equation 2, to find y:

    y = 5 (9) + 7 = 45 + 7 = 52
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