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Today, 09:55

Find the ninth term of the

geometric sequence, given the

first term and common ratio.

a1=1 and r=-1/3

+4
Answers (2)
  1. Today, 10:16
    0
    Step-by-step explanation:

    n th term = a (r^ (n-1) - 1) / (r-1)

    Ninth term = 1 * [ (-1/3) ⁸ - 1 ] / (-1/3 - 1)

    = (1/6561) - 1 / (-1 - 3/3) = [ (1 - 6561) / 6561] / [-4/3]

    = [-6560/6561] / - 4/3

    = - 6560 * 3 / 6561 * - 4

    = 1640 / 2187
  2. Today, 10:20
    0
    1 (-1/3) ^8

    Answer: 1/6561
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