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15 July, 20:20

What distance does a train travel while slowing from 28 m/s to zero in 12 s?

168 m

178 m

236 m

291 m

none of the above

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Answers (1)
  1. 15 July, 20:29
    0
    V₁ = initial speed = 28 m/s

    v₂ = final speed = 0 m/s

    Average speed = (v₁+v₂) = (28+0) / 2 = 14 m/s

    d = distance = ?

    t = 12 s

    d = t x (v₁+v₂) / 2

    d = 12 x 14 = 168 m
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