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4 December, 09:13

Find the center of a circle with the equation: x^2 + y^2 - 2y - 8x - 19 = 0

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Answers (1)
  1. 4 December, 09:23
    0
    (4, 1)

    Step-by-step explanation:

    x^2 + y^2 - 2y - 8x - 19 = 0

    We rearrange the terms and complete the square twice.

    x^2 - 8x + y^2 - 2y = 19

    x^2 - 8x + 16 + y^2 - 2y + 1 = 19 + 16 + 1

    (x - 4) ^2 + (y - 1) ^2 = 6^2

    The center is (4, 1)
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