The larger of two numbers is nine more than four times the smaller number the sum of the two numbers is 59 find the two numbers

Smaller number = x

Larger number = 4x + 9

sum of the two numbers is 59

x + (4x + 9) = 59

Solve for x, which is the smaller number

x + (4x + 9) = 59

x + 4x + 9 = 59

5x + 9 = 59

5x = 59-9

5x = 50

5x / 5 = 50 / 5

x = 10

Smaller number = 10

Larger Number: Insert 10 into x

4x + 9

4 (10) + 9

40 + 9 = 49

Larger number = 49

Smaller number = 10

Smaller + Larger = 59

10 + 49 = 59