What substitution should be used to rewrite 6 (x + 5) 2 + 5 (x + 5) - 4 = 0 as a quadratic equation?

Step-by-step explanation:

put x+5=t

6t²+5t-4=0

solve for t and then find x

6t²+8t-3t-4=0

2t (3t+4) - 1 (3t+4) = 0

(3t+4) (2t-1) = 0

t=-4/3,1/2

x+5=-4/3

x=-4/3-5=-19/3

or x+5=1/2

x=1/2-5=-9/2

(6 + 5) (x + 5) - 4 = 0