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15 August, 09:59

If 76+2f (x) + x^2 (f (x)) ^3=0 and f (3) = - 2, find f' (3).

f' (3) =

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  1. 15 August, 10:21
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    2f' (x) + 2x (f (x)) ^3+3x^2 (f' (x)) = 0

    f (3) = - 2, x=3

    2f' (3) + 2*3*-2^3+3*-2^2*f' (3) = 0

    2f' (3) - 48+12f' (3) = 0

    14f' (3) = 48

    f' (3) = 48/14=24/7
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