An armadillo is startled by a coyote and jumps straight into the air, creating the shape of a parabola. The parabola can be represented by the equation h=-16t^2+46t+6

a. How high is the armadillo after 0.5 seconds?

b. After how many seconds does it land on the ground?

Question

Addisyn Lawson

Mathematics

9 August, 20:20

An armadillo is startled by a coyote and jumps straight into the air, creating the shape of a parabola. The parabola can be represented by the equation h=-16t^2+46t+6

a. How high is the armadillo after 0.5 seconds?

b. After how many seconds does it land on the ground?

+3

Answers (1)

Know the Answer?

Areli Mosley · Answer 1

a) 25 units

b) 3 seconds

Step-by-step explanation:

a) h = - 16t² + 46t + 6

t = 0.5

h = - 16 (0.5) ² + 46 (0.5) + 6

h = 25

b) - 16t² + 46t + 6 = 0

8t² - 23t - 3 = 0

8t² - 24t + t - 3 = 0

8t (t - 3) + (t - 3) = 0

(8t + 1) (t - 3) = 0

t = - ⅛, 3

t = 3 seconds

An armadillo is startled by a coyote and jumps straight into the air, creating the shape of a parabola. The parabola can be represented by the equation h=-16t^2+46t+6a. How high is the armadillo after 0.5 seconds?b. After how many seconds does it land on the ground?

An armadillo is startled by a coyote and jumps straight into the air, creating the shape of a parabola. The parabola can be represented by the equation h=-16t^2+46t+6

a. How high is the armadillo after 0.5 seconds?

b. After how many seconds does it land on the ground?