During a dig, an archaeological team starts at an elevation of - 512 feet. At a rate of 234 feet per hour, the team digs deeper into the surface for 312 hours. For the next 412 hours, the team digs at a rate of 1512 feet per hour. Then the team quits for the day.

Are you referring to this question?

During a dig, an archaeological team starts at an elevation of - 5 1/2 feet. At a rate of 2 3/4 feet per hour, the team digs deeper into the surface for 3 1/2 hours. For the next 4 1/2 hours, the team digs at a rate of 1 5/12 feet per hour. Then the team quits for the day.

How many feet did the archaeological team dig after 3 1/2 hours?

What was the team's elevation at the end of the day?

If so, then let us find out the elevation.

The rate of their dig is 2 3/4 ft per hr for 3 1/2 hours, then the total distance dug after 3 1/2 hours should be: 9 5/8 ft

Here’s how we get the total distance:

First, change mixed number into improper fraction and proceed to multiplication

2 3/4--> 11/4 and 3 1/2 becomes 7/2

Multiply.

11/4 x 7/2 = 77/8

Simplify 77/8--> 9 5/8 ft

Let us move on at the rate of 1 5/12 ft per hr for the next 4 1/2 hr,

Following the same procedure as above, the distance would be: 6 9/24 ft

Distance = 1 5/12 x 4 1/2

= 17/12 x 9/2

= 153/24

= 6 9/24 ft

Thus, to sum up everything, they have a total dug of:

9 5/8 + 6 9/24 = 9 15/24 + 6 9/24 = 16 ft

Then, their elevation on that day is - 5 1/2 - 16 = - 21 1/2 ft