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19 July, 14:20

find the area of an area of an equilateral triangle (regular 3-gon) with the given measurement 9-inch perimeter. A=sq. in.

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  1. 19 July, 14:24
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    Area = side^2 * sqrt (3) / 4

    If 9 inch perimeter then side = 3

    Area = 3^3 * sqrt (3) / 4

    Area = (9 / 4) * sqrt (3)

    Area = 3.897114317 square inches
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