Ask Question
4 September, 06:22

A classic counting problem is to determine the number of different ways that the letters of "dissipate" can be arranged. Find that number

+5
Answers (1)
  1. 4 September, 06:31
    0
    90720 ways

    Step-by-step explanation:

    Since there are 9 letters, there are 9! ways to arrange them. However since there are repeating letters, we have to divide to remove the duplicates accordingly. There are 2 's' and 2 'i' hence:

    Number of way to arrange 'dissipate' = 9! / (2! x 2!) = 90720 ways

    Hence there are 90720 ways to have the number of dissipate in the letter.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A classic counting problem is to determine the number of different ways that the letters of "dissipate" can be arranged. Find that number ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers