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5 February, 17:51

A classic counting problem is to determine the number of different ways that the letters of "dissipate" can be arranged. Find that number

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  1. 5 February, 19:07
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    90720 ways

    Step-by-step explanation:

    Since there are 9 letters, there are 9! ways to arrange them. However since there are repeating letters, we have to divide to remove the duplicates accordingly. There are 2 's' and 2 'i' hence:

    Number of way to arrange 'dissipate' = 9! / (2! x 2!) = 90720 ways

    Hence there are 90720 ways to have the number of dissipate in the letter.
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