A classic counting problem is to determine the number of different ways that the letters of "dissipate" can be arranged. Find that number

Question

Remington

Mathematics

4 September, 06:22

A classic counting problem is to determine the number of different ways that the letters of "dissipate" can be arranged. Find that number

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Answers (1)

Know the Answer?

Alannah Walsh · Answer 1

90720 ways

Step-by-step explanation:

Since there are 9 letters, there are 9! ways to arrange them. However since there are repeating letters, we have to divide to remove the duplicates accordingly. There are 2 's' and 2 'i' hence:

Number of way to arrange 'dissipate' = 9! / (2! x 2!) = 90720 ways

Hence there are 90720 ways to have the number of dissipate in the letter.