Rubin is 5 years older than one third Terry's age. Sheldon is three years younger than 2 times Rubin's age. Define a variable and write an expression to represent Rubin's age. Then find Rubin age and Sheldon age if Terry is 6 years old.

Question

Clay Villa

Mathematics

6 December, 14:02

Rubin is 5 years older than one third Terry's age. Sheldon is three years younger than 2 times Rubin's age. Define a variable and write an expression to represent Rubin's age. Then find Rubin age and Sheldon age if Terry is 6 years old.

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Answers (2)

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Blaze Garner · Answer 1

Blaze Garner 6 December, 14:21

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Ruby is 7 Sheldon is 11

Eileen Wu · Answer 2

Let Terry's age be x

Terry = x

Rubin is 5 years older than one third Terry’s age

Rubin = 5 + 1/3x

Sheldon is three years younger than 2 times Rubin’s age.

Sheldon = 2 (5 + 1/3x) - 3

If Terry is 6,

Rubin = 5 + 1/3 (6) = 5 + 2 = 7

Sheldon = 2 (5 + 1/3 (6)) - 3 = 11

Ans: Rubin is 7 and Sheldon is 11