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Cassie Stout
Mathematics
29 July, 17:18
Solve sin2x + 4sin x + 3 = 0
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Mikayla Gross
29 July, 17:44
0
Sin² x + 4 sin x + 3 = 0
Substitution: u = sin x
u² + 4 u + 3 = 0
u² + 3 u + u + 3 = 0
u (u + 3) + (u + 3) = 0
(u + 3) (u + 1) = 0
u = - 3, u = - 1;
sin x = - 3 (false)
sin x = - 1
Answer:
x = 3 π / 2 + 2 k π, k ∈ Z
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