Chris bought 2 chicken sandwiches and 3 bowls of vegetable soup for $50, not including tax. Jim bought 1 chicken sandwich and 2 bowls of vegetable soup for$9.50, not including tax. What was the cost of a bowl of soup?

C=chicken sandwich

v=bowl of vegetable soup

so Chris: 2c+3v=50 and

Jim: 1c+2v=9.5

so 2c+3v=50 and c+2v=9.5

c+2v=9.5

subtract 2 v from both sides

c=9.5-2v

subsitute c=9.5-2v for c in 2c+3v=50

2 (9.5-2v) + 3v=50

distribute

19-4v+3v=50

add like terms

19-v=50

add v to both sides

19=50+v

subtract 50 from both sides

-31=v

the value of foods are never negative so there is no solution

2c + 3v = $50;

1c + 2v = $9.50 / * 2;

2c + 4v = $19; 2c + 3v + v = $19; $50 + v = $19; v = - $31; False, because v > 0;

There is something wrong with this problem!