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23 December, 21:26

Which domain restrictions apply to the rational expression?

x^2+5x+6/x^2-9

Select two correct answers.

Question 1 options:

x≠-3

x≠-2

x≠-1

x≠1

x≠2

x≠3

+3
Answers (1)
  1. 23 December, 21:46
    0
    1) it must be fulfilled that the denominator is different from zero, then for this expression

    x^2 - 9 ⇒ x^2-3^2 = (x-3) (x+3) ⇒ (x-3) (x+3) = 0 ⇒ x = 3 o x = - 3, the dominium is all numbers reals except 3 and - 3
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